Question
A satellite is revolving in a circular orbit at a distance of 3400 km. calculate the orbital velocity and the period of revolution of the satellite. Radius of the earth = 6400 km and g = 9.8 ms^{ –2}.

1.66 hours

2.67 hours

3.68 hours

4.69 hours
medium
Solution
2.67 hours
Radius of the earth, R_{e} = 6400 km = 6.4 × 10^{6} m.
Radius of the orbit of the satellite is
Period of revolution, seconds = 2.67 hours.
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